Algorithm for computing polynomial coefficients
In mathematics , divided differences is an algorithm , historically used for computing tables of logarithms and trigonometric functions .[citation needed ] Charles Babbage 's difference engine , an early mechanical calculator , was designed to use this algorithm in its operation.[ 1]
Divided differences is a recursive division process. Given a sequence of data points
(
x
0
,
y
0
)
,
…
,
(
x
n
,
y
n
)
{\displaystyle (x_{0},y_{0}),\ldots ,(x_{n},y_{n})}
, the method calculates the coefficients of the interpolation polynomial of these points in the Newton form .
Definition
Given n + 1 data points
(
x
0
,
y
0
)
,
…
,
(
x
n
,
y
n
)
{\displaystyle (x_{0},y_{0}),\ldots ,(x_{n},y_{n})}
where the
x
k
{\displaystyle x_{k}
are assumed to be pairwise distinct, the forward divided differences are defined as:
[
y
k
]
:=
y
k
,
k
∈
{
0
,
…
,
n
}
[
y
k
,
…
,
y
k
+
j
]
:=
[
y
k
+
1
,
…
,
y
k
+
j
]
−
[
y
k
,
…
,
y
k
+
j
−
1
]
x
k
+
j
−
x
k
,
k
∈
{
0
,
…
,
n
−
j
}
,
j
∈
{
1
,
…
,
n
}
.
{\displaystyle {\begin{aligned}{\mathopen {[}y_{k}]&:=y_{k},&&k\in \{0,\ldots ,n\}\\{\mathopen {[}y_{k},\ldots ,y_{k+j}]&:={\frac {[y_{k+1},\ldots ,y_{k+j}]-[y_{k},\ldots ,y_{k+j-1}]}{x_{k+j}-x_{k},&&k\in \{0,\ldots ,n-j\},\ j\in \{1,\ldots ,n\}.\end{aligned}
To make the recursive process of computation clearer, the divided differences can be put in tabular form, where the columns correspond to the value of j above, and each entry in the table is computed from the difference of the entries to its immediate lower left and to its immediate upper left, divided by a difference of corresponding x- values:
x
0
y
0
=
[
y
0
]
[
y
0
,
y
1
]
x
1
y
1
=
[
y
1
]
[
y
0
,
y
1
,
y
2
]
[
y
1
,
y
2
]
[
y
0
,
y
1
,
y
2
,
y
3
]
x
2
y
2
=
[
y
2
]
[
y
1
,
y
2
,
y
3
]
[
y
2
,
y
3
]
x
3
y
3
=
[
y
3
]
{\displaystyle {\begin{matrix}x_{0}&y_{0}=[y_{0}]&&&\\&&[y_{0},y_{1}]&&\\x_{1}&y_{1}=[y_{1}]&&[y_{0},y_{1},y_{2}]&\\&&[y_{1},y_{2}]&&[y_{0},y_{1},y_{2},y_{3}]\\x_{2}&y_{2}=[y_{2}]&&[y_{1},y_{2},y_{3}]&\\&&[y_{2},y_{3}]&&\\x_{3}&y_{3}=[y_{3}]&&&\\\end{matrix}
Notation
Note that the divided difference
[
y
k
,
…
,
y
k
+
j
]
{\displaystyle [y_{k},\ldots ,y_{k+j}]}
depends on the values
x
k
,
…
,
x
k
+
j
{\displaystyle x_{k},\ldots ,x_{k+j}
and
y
k
,
…
,
y
k
+
j
{\displaystyle y_{k},\ldots ,y_{k+j}
, but the notation hides the dependency on the x -values. If the data points are given by a function f ,
(
x
0
,
y
0
)
,
…
,
(
x
k
,
y
n
)
=
(
x
0
,
f
(
x
0
)
)
,
…
,
(
x
n
,
f
(
x
n
)
)
{\displaystyle (x_{0},y_{0}),\ldots ,(x_{k},y_{n})=(x_{0},f(x_{0})),\ldots ,(x_{n},f(x_{n}))}
one sometimes writes the divided difference in the notation
f
[
x
k
,
…
,
x
k
+
j
]
=
def
[
f
(
x
k
)
,
…
,
f
(
x
k
+
j
)
]
=
[
y
k
,
…
,
y
k
+
j
]
.
{\displaystyle f[x_{k},\ldots ,x_{k+j}]\ {\stackrel {\text{def}{=}\ [f(x_{k}),\ldots ,f(x_{k+j})]=[y_{k},\ldots ,y_{k+j}].}
Other notations for the divided difference of the function ƒ on the nodes x 0 , ..., x n are:
f
[
x
k
,
…
,
x
k
+
j
]
=
[
x
0
,
…
,
x
n
]
f
=
[
x
0
,
…
,
x
n
;
f
]
=
D
[
x
0
,
…
,
x
n
]
f
.
{\displaystyle f[x_{k},\ldots ,x_{k+j}]={\mathopen {[}x_{0},\ldots ,x_{n}]f={\mathopen {[}x_{0},\ldots ,x_{n};f]=D[x_{0},\ldots ,x_{n}]f.}
Example
Divided differences for
k
=
0
{\displaystyle k=0}
and the first few values of
j
{\displaystyle j}
:
[
y
0
]
=
y
0
[
y
0
,
y
1
]
=
y
1
−
y
0
x
1
−
x
0
[
y
0
,
y
1
,
y
2
]
=
[
y
1
,
y
2
]
−
[
y
0
,
y
1
]
x
2
−
x
0
=
y
2
−
y
1
x
2
−
x
1
−
y
1
−
y
0
x
1
−
x
0
x
2
−
x
0
=
y
2
−
y
1
(
x
2
−
x
1
)
(
x
2
−
x
0
)
−
y
1
−
y
0
(
x
1
−
x
0
)
(
x
2
−
x
0
)
[
y
0
,
y
1
,
y
2
,
y
3
]
=
[
y
1
,
y
2
,
y
3
]
−
[
y
0
,
y
1
,
y
2
]
x
3
−
x
0
{\displaystyle {\begin{aligned}{\mathopen {[}y_{0}]&=y_{0}\\{\mathopen {[}y_{0},y_{1}]&={\frac {y_{1}-y_{0}{x_{1}-x_{0}\\{\mathopen {[}y_{0},y_{1},y_{2}]&={\frac {\mathopen {[}y_{1},y_{2}]-{\mathopen {[}y_{0},y_{1}]}{x_{2}-x_{0}={\frac {\frac {y_{2}-y_{1}{x_{2}-x_{1}-{\frac {y_{1}-y_{0}{x_{1}-x_{0}{x_{2}-x_{0}={\frac {y_{2}-y_{1}{(x_{2}-x_{1})(x_{2}-x_{0})}-{\frac {y_{1}-y_{0}{(x_{1}-x_{0})(x_{2}-x_{0})}\\{\mathopen {[}y_{0},y_{1},y_{2},y_{3}]&={\frac {\mathopen {[}y_{1},y_{2},y_{3}]-{\mathopen {[}y_{0},y_{1},y_{2}]}{x_{3}-x_{0}\end{aligned}
Thus, the table corresponding to these terms upto two columns has the following form:
x
0
y
0
y
1
−
y
0
x
1
−
x
0
x
1
y
1
y
2
−
y
1
x
2
−
x
1
−
y
1
−
y
0
x
1
−
x
0
x
2
−
x
0
y
2
−
y
1
x
2
−
x
1
x
2
y
2
⋮
⋮
⋮
⋮
⋮
x
n
y
n
{\displaystyle {\begin{matrix}x_{0}&y_{0}&&\\&&{y_{1}-y_{0} \over x_{1}-x_{0}&\\x_{1}&y_{1}&&{y_{2}-y_{1} \over x_{2}-x_{1}-{y_{1}-y_{0} \over x_{1}-x_{0} \over x_{2}-x_{0}\\&&{y_{2}-y_{1} \over x_{2}-x_{1}&\\x_{2}&y_{2}&&\vdots \\&&\vdots &\\\vdots &&&\vdots \\&&\vdots &\\x_{n}&y_{n}&&\\\end{matrix}
Properties
Linearity
(
f
+
g
)
[
x
0
,
…
,
x
n
]
=
f
[
x
0
,
…
,
x
n
]
+
g
[
x
0
,
…
,
x
n
]
(
λ
⋅
f
)
[
x
0
,
…
,
x
n
]
=
λ
⋅
f
[
x
0
,
…
,
x
n
]
{\displaystyle {\begin{aligned}(f+g)[x_{0},\dots ,x_{n}]&=f[x_{0},\dots ,x_{n}]+g[x_{0},\dots ,x_{n}]\\(\lambda \cdot f)[x_{0},\dots ,x_{n}]&=\lambda \cdot f[x_{0},\dots ,x_{n}]\end{aligned}
Leibniz rule
(
f
⋅
g
)
[
x
0
,
…
,
x
n
]
=
f
[
x
0
]
⋅
g
[
x
0
,
…
,
x
n
]
+
f
[
x
0
,
x
1
]
⋅
g
[
x
1
,
…
,
x
n
]
+
⋯
+
f
[
x
0
,
…
,
x
n
]
⋅
g
[
x
n
]
=
∑
r
=
0
n
f
[
x
0
,
…
,
x
r
]
⋅
g
[
x
r
,
…
,
x
n
]
{\displaystyle (f\cdot g)[x_{0},\dots ,x_{n}]=f[x_{0}]\cdot g[x_{0},\dots ,x_{n}]+f[x_{0},x_{1}]\cdot g[x_{1},\dots ,x_{n}]+\dots +f[x_{0},\dots ,x_{n}]\cdot g[x_{n}]=\sum _{r=0}^{n}f[x_{0},\ldots ,x_{r}]\cdot g[x_{r},\ldots ,x_{n}]}
Divided differences are symmetric: If
σ
:
{
0
,
…
,
n
}
→
{
0
,
…
,
n
}
{\displaystyle \sigma :\{0,\dots ,n\}\to \{0,\dots ,n\}
is a permutation then
f
[
x
0
,
…
,
x
n
]
=
f
[
x
σ
(
0
)
,
…
,
x
σ
(
n
)
]
{\displaystyle f[x_{0},\dots ,x_{n}]=f[x_{\sigma (0)},\dots ,x_{\sigma (n)}]}
Polynomial interpolation in the Newton form : if
P
{\displaystyle P}
is a polynomial function of degree
≤
n
{\displaystyle \leq n}
, and
p
[
x
0
,
…
,
x
n
]
{\displaystyle p[x_{0},\dots ,x_{n}]}
is the divided difference, then
P
n
−
1
(
x
)
=
p
[
x
0
]
+
p
[
x
0
,
x
1
]
(
x
−
x
0
)
+
p
[
x
0
,
x
1
,
x
2
]
(
x
−
x
0
)
(
x
−
x
1
)
+
⋯
+
p
[
x
0
,
…
,
x
n
]
(
x
−
x
0
)
(
x
−
x
1
)
⋯
(
x
−
x
n
−
1
)
{\displaystyle P_{n-1}(x)=p[x_{0}]+p[x_{0},x_{1}](x-x_{0})+p[x_{0},x_{1},x_{2}](x-x_{0})(x-x_{1})+\cdots +p[x_{0},\ldots ,x_{n}](x-x_{0})(x-x_{1})\cdots (x-x_{n-1})}
If
p
{\displaystyle p}
is a polynomial function of degree
<
n
{\displaystyle <n}
, then
p
[
x
0
,
…
,
x
n
]
=
0.
{\displaystyle p[x_{0},\dots ,x_{n}]=0.}
Mean value theorem for divided differences : if
f
{\displaystyle f}
is n times differentiable, then
f
[
x
0
,
…
,
x
n
]
=
f
(
n
)
(
ξ
)
n
!
{\displaystyle f[x_{0},\dots ,x_{n}]={\frac {f^{(n)}(\xi )}{n!}
for a number
ξ
{\displaystyle \xi }
in the open interval determined by the smallest and largest of the
x
k
{\displaystyle x_{k}
's.
The divided difference scheme can be put into an upper triangular matrix :
T
f
(
x
0
,
…
,
x
n
)
=
(
f
[
x
0
]
f
[
x
0
,
x
1
]
f
[
x
0
,
x
1
,
x
2
]
…
f
[
x
0
,
…
,
x
n
]
0
f
[
x
1
]
f
[
x
1
,
x
2
]
…
f
[
x
1
,
…
,
x
n
]
0
0
f
[
x
2
]
…
f
[
x
2
,
…
,
x
n
]
⋮
⋮
⋱
⋮
0
0
0
…
f
[
x
n
]
)
.
{\displaystyle T_{f}(x_{0},\dots ,x_{n})={\begin{pmatrix}f[x_{0}]&f[x_{0},x_{1}]&f[x_{0},x_{1},x_{2}]&\ldots &f[x_{0},\dots ,x_{n}]\\0&f[x_{1}]&f[x_{1},x_{2}]&\ldots &f[x_{1},\dots ,x_{n}]\\0&0&f[x_{2}]&\ldots &f[x_{2},\dots ,x_{n}]\\\vdots &\vdots &&\ddots &\vdots \\0&0&0&\ldots &f[x_{n}]\end{pmatrix}.}
Then it holds
T
f
+
g
(
x
)
=
T
f
(
x
)
+
T
g
(
x
)
{\displaystyle T_{f+g}(x)=T_{f}(x)+T_{g}(x)}
T
λ
f
(
x
)
=
λ
T
f
(
x
)
{\displaystyle T_{\lambda f}(x)=\lambda T_{f}(x)}
if
λ
{\displaystyle \lambda }
is a scalar
T
f
⋅
g
(
x
)
=
T
f
(
x
)
⋅
T
g
(
x
)
{\displaystyle T_{f\cdot g}(x)=T_{f}(x)\cdot T_{g}(x)}
This follows from the Leibniz rule. It means that multiplication of such matrices is commutative . Summarised, the matrices of divided difference schemes with respect to the same set of nodes x form a commutative ring .
Since
T
f
(
x
)
{\displaystyle T_{f}(x)}
is a triangular matrix, its eigenvalues are obviously
f
(
x
0
)
,
…
,
f
(
x
n
)
{\displaystyle f(x_{0}),\dots ,f(x_{n})}
.
Let
δ
ξ
{\displaystyle \delta _{\xi }
be a Kronecker delta -like function, that is
δ
ξ
(
t
)
=
{
1
:
t
=
ξ
,
0
:
else
.
{\displaystyle \delta _{\xi }(t)={\begin{cases}1&:t=\xi ,\\0&:{\mbox{else}.\end{cases}
Obviously
f
⋅
δ
ξ
=
f
(
ξ
)
⋅
δ
ξ
{\displaystyle f\cdot \delta _{\xi }=f(\xi )\cdot \delta _{\xi }
, thus
δ
ξ
{\displaystyle \delta _{\xi }
is an eigenfunction of the pointwise function multiplication. That is
T
δ
x
i
(
x
)
{\displaystyle T_{\delta _{x_{i}(x)}
is somehow an "eigenmatrix " of
T
f
(
x
)
{\displaystyle T_{f}(x)}
:
T
f
(
x
)
⋅
T
δ
x
i
(
x
)
=
f
(
x
i
)
⋅
T
δ
x
i
(
x
)
{\displaystyle T_{f}(x)\cdot T_{\delta _{x_{i}(x)=f(x_{i})\cdot T_{\delta _{x_{i}(x)}
. However, all columns of
T
δ
x
i
(
x
)
{\displaystyle T_{\delta _{x_{i}(x)}
are multiples of each other, the matrix rank of
T
δ
x
i
(
x
)
{\displaystyle T_{\delta _{x_{i}(x)}
is 1. So you can compose the matrix of all eigenvectors of
T
f
(
x
)
{\displaystyle T_{f}(x)}
from the
i
{\displaystyle i}
-th column of each
T
δ
x
i
(
x
)
{\displaystyle T_{\delta _{x_{i}(x)}
. Denote the matrix of eigenvectors with
U
(
x
)
{\displaystyle U(x)}
. Example
U
(
x
0
,
x
1
,
x
2
,
x
3
)
=
(
1
1
(
x
1
−
x
0
)
1
(
x
2
−
x
0
)
(
x
2
−
x
1
)
1
(
x
3
−
x
0
)
(
x
3
−
x
1
)
(
x
3
−
x
2
)
0
1
1
(
x
2
−
x
1
)
1
(
x
3
−
x
1
)
(
x
3
−
x
2
)
0
0
1
1
(
x
3
−
x
2
)
0
0
0
1
)
{\displaystyle U(x_{0},x_{1},x_{2},x_{3})={\begin{pmatrix}1&{\frac {1}{(x_{1}-x_{0})}&{\frac {1}{(x_{2}-x_{0})(x_{2}-x_{1})}&{\frac {1}{(x_{3}-x_{0})(x_{3}-x_{1})(x_{3}-x_{2})}\\0&1&{\frac {1}{(x_{2}-x_{1})}&{\frac {1}{(x_{3}-x_{1})(x_{3}-x_{2})}\\0&0&1&{\frac {1}{(x_{3}-x_{2})}\\0&0&0&1\end{pmatrix}
The diagonalization of
T
f
(
x
)
{\displaystyle T_{f}(x)}
can be written as
U
(
x
)
⋅
diag
(
f
(
x
0
)
,
…
,
f
(
x
n
)
)
=
T
f
(
x
)
⋅
U
(
x
)
.
{\displaystyle U(x)\cdot \operatorname {diag} (f(x_{0}),\dots ,f(x_{n}))=T_{f}(x)\cdot U(x).}
Polynomials and power series
The matrix
J
=
(
x
0
1
0
0
⋯
0
0
x
1
1
0
⋯
0
0
0
x
2
1
0
⋮
⋮
⋱
⋱
0
0
0
0
⋱
1
0
0
0
0
x
n
)
{\displaystyle J={\begin{pmatrix}x_{0}&1&0&0&\cdots &0\\0&x_{1}&1&0&\cdots &0\\0&0&x_{2}&1&&0\\\vdots &\vdots &&\ddots &\ddots &\\0&0&0&0&\;\ddots &1\\0&0&0&0&&x_{n}\end{pmatrix}
contains the divided difference scheme for the identity function with respect to the nodes
x
0
,
…
,
x
n
{\displaystyle x_{0},\dots ,x_{n}
, thus
J
m
{\displaystyle J^{m}
contains the divided differences for the power function with exponent
m
{\displaystyle m}
.
Consequently, you can obtain the divided differences for a polynomial function
p
{\displaystyle p}
by applying
p
{\displaystyle p}
to the matrix
J
{\displaystyle J}
: If
p
(
ξ
)
=
a
0
+
a
1
⋅
ξ
+
⋯
+
a
m
⋅
ξ
m
{\displaystyle p(\xi )=a_{0}+a_{1}\cdot \xi +\dots +a_{m}\cdot \xi ^{m}
and
p
(
J
)
=
a
0
+
a
1
⋅
J
+
⋯
+
a
m
⋅
J
m
{\displaystyle p(J)=a_{0}+a_{1}\cdot J+\dots +a_{m}\cdot J^{m}
then
T
p
(
x
)
=
p
(
J
)
.
{\displaystyle T_{p}(x)=p(J).}
This is known as Opitz' formula .[ 2] [ 3]
Now consider increasing the degree of
p
{\displaystyle p}
to infinity, i.e. turn the Taylor polynomial into a Taylor series .
Let
f
{\displaystyle f}
be a function which corresponds to a power series .
You can compute the divided difference scheme for
f
{\displaystyle f}
by applying the corresponding matrix series to
J
{\displaystyle J}
:
If
f
(
ξ
)
=
∑
k
=
0
∞
a
k
ξ
k
{\displaystyle f(\xi )=\sum _{k=0}^{\infty }a_{k}\xi ^{k}
and
f
(
J
)
=
∑
k
=
0
∞
a
k
J
k
{\displaystyle f(J)=\sum _{k=0}^{\infty }a_{k}J^{k}
then
T
f
(
x
)
=
f
(
J
)
.
{\displaystyle T_{f}(x)=f(J).}
Alternative characterizations
f
[
x
0
]
=
f
(
x
0
)
f
[
x
0
,
x
1
]
=
f
(
x
0
)
(
x
0
−
x
1
)
+
f
(
x
1
)
(
x
1
−
x
0
)
f
[
x
0
,
x
1
,
x
2
]
=
f
(
x
0
)
(
x
0
−
x
1
)
⋅
(
x
0
−
x
2
)
+
f
(
x
1
)
(
x
1
−
x
0
)
⋅
(
x
1
−
x
2
)
+
f
(
x
2
)
(
x
2
−
x
0
)
⋅
(
x
2
−
x
1
)
f
[
x
0
,
x
1
,
x
2
,
x
3
]
=
f
(
x
0
)
(
x
0
−
x
1
)
⋅
(
x
0
−
x
2
)
⋅
(
x
0
−
x
3
)
+
f
(
x
1
)
(
x
1
−
x
0
)
⋅
(
x
1
−
x
2
)
⋅
(
x
1
−
x
3
)
+
f
(
x
2
)
(
x
2
−
x
0
)
⋅
(
x
2
−
x
1
)
⋅
(
x
2
−
x
3
)
+
f
(
x
3
)
(
x
3
−
x
0
)
⋅
(
x
3
−
x
1
)
⋅
(
x
3
−
x
2
)
f
[
x
0
,
…
,
x
n
]
=
∑
j
=
0
n
f
(
x
j
)
∏
k
∈
{
0
,
…
,
n
}
∖
{
j
}
(
x
j
−
x
k
)
{\displaystyle {\begin{aligned}f[x_{0}]&=f(x_{0})\\f[x_{0},x_{1}]&={\frac {f(x_{0})}{(x_{0}-x_{1})}+{\frac {f(x_{1})}{(x_{1}-x_{0})}\\f[x_{0},x_{1},x_{2}]&={\frac {f(x_{0})}{(x_{0}-x_{1})\cdot (x_{0}-x_{2})}+{\frac {f(x_{1})}{(x_{1}-x_{0})\cdot (x_{1}-x_{2})}+{\frac {f(x_{2})}{(x_{2}-x_{0})\cdot (x_{2}-x_{1})}\\f[x_{0},x_{1},x_{2},x_{3}]&={\frac {f(x_{0})}{(x_{0}-x_{1})\cdot (x_{0}-x_{2})\cdot (x_{0}-x_{3})}+{\frac {f(x_{1})}{(x_{1}-x_{0})\cdot (x_{1}-x_{2})\cdot (x_{1}-x_{3})}+\\&\quad \quad {\frac {f(x_{2})}{(x_{2}-x_{0})\cdot (x_{2}-x_{1})\cdot (x_{2}-x_{3})}+{\frac {f(x_{3})}{(x_{3}-x_{0})\cdot (x_{3}-x_{1})\cdot (x_{3}-x_{2})}\\f[x_{0},\dots ,x_{n}]&=\sum _{j=0}^{n}{\frac {f(x_{j})}{\prod _{k\in \{0,\dots ,n\}\setminus \{j\}(x_{j}-x_{k})}\end{aligned}
With the help of the polynomial function
ω
(
ξ
)
=
(
ξ
−
x
0
)
⋯
(
ξ
−
x
n
)
{\displaystyle \omega (\xi )=(\xi -x_{0})\cdots (\xi -x_{n})}
this can be written as
f
[
x
0
,
…
,
x
n
]
=
∑
j
=
0
n
f
(
x
j
)
ω
′
(
x
j
)
.
{\displaystyle f[x_{0},\dots ,x_{n}]=\sum _{j=0}^{n}{\frac {f(x_{j})}{\omega '(x_{j})}.}
If
x
0
<
x
1
<
⋯
<
x
n
{\displaystyle x_{0}<x_{1}<\cdots <x_{n}
and
n
≥
1
{\displaystyle n\geq 1}
, the divided differences can be expressed as[ 4]
f
[
x
0
,
…
,
x
n
]
=
1
(
n
−
1
)
!
∫
x
0
x
n
f
(
n
)
(
t
)
B
n
−
1
(
t
)
d
t
{\displaystyle f[x_{0},\ldots ,x_{n}]={\frac {1}{(n-1)!}\int _{x_{0}^{x_{n}f^{(n)}(t)\;B_{n-1}(t)\,dt}
where
f
(
n
)
{\displaystyle f^{(n)}
is the
n
{\displaystyle n}
-th derivative of the function
f
{\displaystyle f}
and
B
n
−
1
{\displaystyle B_{n-1}
is a certain B-spline of degree
n
−
1
{\displaystyle n-1}
for the data points
x
0
,
…
,
x
n
{\displaystyle x_{0},\dots ,x_{n}
, given by the formula
B
n
−
1
(
t
)
=
∑
k
=
0
n
(
max
(
0
,
x
k
−
t
)
)
n
−
1
ω
′
(
x
k
)
{\displaystyle B_{n-1}(t)=\sum _{k=0}^{n}{\frac {(\max(0,x_{k}-t))^{n-1}{\omega '(x_{k})}
This is a consequence of the Peano kernel theorem ; it is called the Peano form of the divided differences and
B
n
−
1
{\displaystyle B_{n-1}
is the Peano kernel for the divided differences, all named after Giuseppe Peano .
Forward and backward differences
When the data points are equidistantly distributed we get the special case called forward differences . They are easier to calculate than the more general divided differences.
Given n +1 data points
(
x
0
,
y
0
)
,
…
,
(
x
n
,
y
n
)
{\displaystyle (x_{0},y_{0}),\ldots ,(x_{n},y_{n})}
with
x
k
=
x
0
+
k
h
,
for
k
=
0
,
…
,
n
and fixed
h
>
0
{\displaystyle x_{k}=x_{0}+kh,\ {\text{ for }\ k=0,\ldots ,n{\text{ and fixed }h>0}
the forward differences are defined as
Δ
(
0
)
y
k
:=
y
k
,
k
=
0
,
…
,
n
Δ
(
j
)
y
k
:=
Δ
(
j
−
1
)
y
k
+
1
−
Δ
(
j
−
1
)
y
k
,
k
=
0
,
…
,
n
−
j
,
j
=
1
,
…
,
n
.
{\displaystyle {\begin{aligned}\Delta ^{(0)}y_{k}&:=y_{k},\qquad k=0,\ldots ,n\\\Delta ^{(j)}y_{k}&:=\Delta ^{(j-1)}y_{k+1}-\Delta ^{(j-1)}y_{k},\qquad k=0,\ldots ,n-j,\ j=1,\dots ,n.\end{aligned}
whereas the backward differences are defined as:
∇
(
0
)
y
k
:=
y
k
,
k
=
0
,
…
,
n
∇
(
j
)
y
k
:=
∇
(
j
−
1
)
y
k
−
∇
(
j
−
1
)
y
k
−
1
,
k
=
0
,
…
,
n
−
j
,
j
=
1
,
…
,
n
.
{\displaystyle {\begin{aligned}\nabla ^{(0)}y_{k}&:=y_{k},\qquad k=0,\ldots ,n\\\nabla ^{(j)}y_{k}&:=\nabla ^{(j-1)}y_{k}-\nabla ^{(j-1)}y_{k-1},\qquad k=0,\ldots ,n-j,\ j=1,\dots ,n.\end{aligned}
Thus the forward difference table is written as:
y
0
Δ
y
0
y
1
Δ
2
y
0
Δ
y
1
Δ
3
y
0
y
2
Δ
2
y
1
Δ
y
2
y
3
{\displaystyle {\begin{matrix}y_{0}&&&\\&\Delta y_{0}&&\\y_{1}&&\Delta ^{2}y_{0}&\\&\Delta y_{1}&&\Delta ^{3}y_{0}\\y_{2}&&\Delta ^{2}y_{1}&\\&\Delta y_{2}&&\\y_{3}&&&\\\end{matrix}
whereas the backwards difference table is written as:
y
0
∇
y
1
y
1
∇
2
y
2
∇
y
2
∇
3
y
3
y
2
∇
2
y
3
∇
y
3
y
3
{\displaystyle {\begin{matrix}y_{0}&&&\\&\nabla y_{1}&&\\y_{1}&&\nabla ^{2}y_{2}&\\&\nabla y_{2}&&\nabla ^{3}y_{3}\\y_{2}&&\nabla ^{2}y_{3}&\\&\nabla y_{3}&&\\y_{3}&&&\\\end{matrix}
The relationship between divided differences and forward differences is[ 5]
[
y
j
,
y
j
+
1
,
…
,
y
j
+
k
]
=
1
k
!
h
k
Δ
(
k
)
y
j
,
{\displaystyle [y_{j},y_{j+1},\ldots ,y_{j+k}]={\frac {1}{k!h^{k}\Delta ^{(k)}y_{j},}
whereas for backward differences:[citation needed ]
[
y
j
,
y
j
−
1
,
…
,
y
j
−
k
]
=
1
k
!
h
k
∇
(
k
)
y
j
.
{\displaystyle [{y}_{j},y_{j-1},\ldots ,{y}_{j-k}]={\frac {1}{k!h^{k}\nabla ^{(k)}y_{j}.}
See also
References
^ Isaacson, Walter (2014). The Innovators . Simon & Schuster. p. 20. ISBN 978-1-4767-0869-0 .
^ de Boor, Carl , Divided Differences , Surv. Approx. Theory 1 (2005), 46–69, [1]
^ Opitz, G. Steigungsmatrizen , Z. Angew. Math. Mech. (1964), 44, T52–T54
^ Skof, Fulvia (2011-04-30). Giuseppe Peano between Mathematics and Logic: Proceeding of the International Conference in honour of Giuseppe Peano on the 150th anniversary of his birth and the centennial of the Formulario Mathematico Torino (Italy) October 2-3, 2008 . Springer Science & Business Media. p. 40. ISBN 978-88-470-1836-5 .
^ Burden, Richard L.; Faires, J. Douglas (2011). Numerical Analysis (9th ed.). Cengage Learning. p. 129 . ISBN 9780538733519 .
Louis Melville Milne-Thomson (2000) [1933]. The Calculus of Finite Differences . American Mathematical Soc. Chapter 1: Divided Differences. ISBN 978-0-8218-2107-7 .
Myron B. Allen; Eli L. Isaacson (1998). Numerical Analysis for Applied Science . John Wiley & Sons. Appendix A. ISBN 978-1-118-03027-1 .
Ron Goldman (2002). Pyramid Algorithms: A Dynamic Programming Approach to Curves and Surfaces for Geometric Modeling . Morgan Kaufmann. Chapter 4:Newton Interpolation and Difference Triangles. ISBN 978-0-08-051547-2 .
External links