Geneva, Ohio
41°48′18″N 80°56′53″W / 41.80500°N 80.94806°W / 41.80500; -80.94806
Geneva is a city in Ashtabula County, Ohio, United States. It is named after Geneva, New York. The population was 5,924 at the 2020 census.
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| Cities | |  Map of Ohio highlighting Ashtabula County |
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| Villages |
- Andover
- Geneva-on-the-Lake
- Jefferson
- North Kingsville
- Orwell
- Roaming Shores
- Rock Creek
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| Townships |
- Andover
- Ashtabula
- Austinburg
- Cherry Valley
- Colebrook
- Denmark
- Dorset
- Geneva
- Harpersfield
- Hartsgrove
- Jefferson
- Kingsville
- Lenox
- Monroe
- Morgan
- New Lyme
- Orwell
- Pierpont
- Plymouth
- Richmond
- Rome
- Saybrook
- Sheffield
- Trumbull
- Wayne
- Williamsfield
- Windsor
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| CDPs |
- Austinburg
- Edgewood
- Kingsville
- Saybrook-on-the-Lake
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Unincorporated
communities |
- Dorset
- Eagleville
- Footville
- Griggs Corners
- Kelloggsville
- Pierpont
- Stanhope‡
- Unionville
- Wick
- Williamsfield
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| Footnotes | ‡This populated place also has portions in an adjacent county or counties |
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